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Silver Member Username: Lord_huggingtonOntario Canada Post Number: 292 Registered: Oct-10 | Would either coil wire down to 1.33 or .67 ohms? If 3 S4's wire into 1.33 ohms and 6 wire into .67 than will 12 wire into 1.33 or will D4 wire into .67? Trying to get closest to 1 ohm and not over 1.33. Thanks. |
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Bronze Member Username: AlonzoubPost Number: 89 Registered: Apr-10 | Yea, 12 D4 subs will wire to .67 ohms. The way I would do it would be to do 4 groups of 3 subs. Each group like this: http://images.the12volt.com/12voltimages/3_4ohm_dvc_267ohm.gif Then wire all 4 groups in parallel to get .67 ohms. |
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Silver Member Username: Lord_huggingtonOntario Canada Post Number: 300 Registered: Oct-10 | Thanks. Confused a little - that diagram is 2.66 ohms, you mean it starts like that as one group and then wiring the 4 groups of 3 with the pos or neg or both will bring it to .67? I ask because one amp is preferable either at .67 or 1.33. Could do 3 1200's but I wouldn't want 3 amps. Can 12 D2's wire into 1.33 ohm? What does that wire down to? For 3600W RMS - would need an AB 500.1 @ 1.33 (5500 * .67 = 3685W) or an amp that is .67 ohm stable and does about 2750W @ 1 ohm (2750 * 1.33 = 3657.5W) for right around 300W each. Does that sound right? |
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Bronze Member Username: AlonzoubPost Number: 91 Registered: Apr-10 | Right, because 2.66/4 = .67 Another way of looking at it would be to simply wire all the INDIVIDUAL subs in series so its like you have 12 8-ohm SVC subs and just wire all 12 subs in parallel. 8/12 = .67 You could do 12 D2's to 1.33 ohms aswell. One way you could achieve this is to make 6 groups each consisting of 2 subs in series-series http://images.the12volt.com/12voltimages/2_2ohm_dvc_8ohm.gif . That would give you 6 groups, each with 8-ohm impedance. Wire all 6 groups in parallel to get 1.33 ohms. 8/6 = 1.33 As for the estimates for the amps, I would interpolate known ratings instead. According to http://www.caraudioclassifieds.org/forum/showthread.php?t=26898 the 500.1 will do: 1 x 2650W @ 2 ohms (14.4V - 1% THD) 1 x 4700W @ 1 ohm (14.4V - 1% THD) So to find a good estimate of the power @ 1.33 ohms I would use linear interpolation. Heres a good online linear interpolation calculator: http://www.ajdesigner.com/phpinterpolation/linear_interpolation_equation.php X1: 1 X2: 1.33 X3: 2 Y1: 4700 Y3: 2650 Plug these values into the linear interpolation formula to find Y2 (this variable symbolizes the power output when impedance is at X2, which in this case we used as 1.33) Y2 = 4023.5 watts So with the AB500.1 you can expect around 4000 watts RMS @ 1.33-ohms assuming the amp has fairly linear output. Sorry about the algebra lesson here, just wanted to make sure you understand how I got my numbers. |
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Silver Member Username: Lord_huggingtonOntario Canada Post Number: 304 Registered: Oct-10 | I love DVC's XD. Thanks man that was really usefull, I've never heard of this trapolizeration module thinger. Seeing those values gives me a high-school headache of the past lol so thanks. I thought I could just do 5000 * .67 but now I realize that it's not linear and only would apply for 1000W (is that correct I dunno!). .67 vs. 1.33? |
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Silver Member Username: MakinblakMonroe/Monticello, La/Ar Post Number: 470 Registered: Oct-10 | I have absolutely no relevant input |
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Silver Member Username: Lord_huggingtonOntario Canada Post Number: 309 Registered: Oct-10 | That's fine, next time link youtube. Tech N9ne bangs . |
