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Ohm impedence

 

Gold Member
Username: Skdooley

Roanoke, VA Usa

Post Number: 1180
Registered: Oct-09
Out of curiosity, what would the final ohm load be for 3 single 4 ohm subs? If they were ran in parallel I'm guessing it'd be a final one ohm load. However, could they be ran in series and if so what ohm load would that result in?
 

Silver Member
Username: Jbpitt

Pittsburgh, Pa. Usa

Post Number: 769
Registered: Jul-09
If ran in series i believe it would be 12 ohms
 

Platinum Member
Username: Nd4spd18

Philadelphia, PA

Post Number: 11346
Registered: Jul-06
parallel = impedance of one speaker / number of speakers
4 / 3 = 1.33 ohms

series = impedance of one speaker * number of speakers
4 * 3 = 12 ohms
 

Platinum Member
Username: Rovin

1 15 = 153 DBs ...Trinidad & T...

Post Number: 16641
Registered: Jul-05
newb alert ! - lol ... j\k


rather than work it out i prefer to use the lazy guy method :

http://www.rockfordfosgate.com/rftech/woofer_wizard.asp

.....
 

Gold Member
Username: Skdooley

Roanoke, VA Usa

Post Number: 1181
Registered: Oct-09
Good deal. I had no idea about the calculations like that.12 ohm would be insane Haha. Thanks for the info guys.
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