Gold Member
Username: Skdooley Roanoke,
VA
Usa
Post Number: 1180 Registered: Oct-09
Posted on
Sunday, September 05, 2010 - 20:06 GMT Out of curiosity, what would the final ohm load be for 3 single 4 ohm subs? If they were ran in parallel I'm guessing it'd be a final one ohm load. However, could they be ran in series and if so what ohm load would that result in?
Silver Member
Username: Jbpitt Pittsburgh,
Pa.
Usa
Post Number: 769 Registered: Jul-09
Posted on
Sunday, September 05, 2010 - 20:29 GMT If ran in series i believe it would be 12 ohms
Platinum Member
Username: Nd4spd18 Philadelphia,
PA
Post Number: 11346 Registered: Jul-06
Posted on
Sunday, September 05, 2010 - 20:57 GMT parallel = impedance of one speaker / number of speakers 4 / 3 = 1.33 ohms series = impedance of one speaker * number of speakers 4 * 3 = 12 ohms
Platinum Member
Username: Rovin 1 15 = 153 DBs ...Trinidad & T...
Post Number: 16641 Registered: Jul-05
Posted on
Monday, September 06, 2010 - 02:54 GMT newb alert ! - lol ... j\k rather than work it out i prefer to use the lazy guy method : http://www.rockfordfosgate.com/rftech/woofer_wizard.asp .....
Gold Member
Username: Skdooley Roanoke,
VA
Usa
Post Number: 1181 Registered: Oct-09
Posted on
Monday, September 06, 2010 - 03:23 GMT Good deal. I had no idea about the calculations like that.12 ohm would be insane Haha. Thanks for the info guys.