Ohm impedence

SKD Gold Member Username: Skdooley Roanoke, VA Usa Post Number: 1180 Registered: Oct-09	Posted on Sunday, September 05, 2010 - 20:06 GMT Out of curiosity, what would the final ohm load be for 3 single 4 ohm subs? If they were ran in parallel I'm guessing it'd be a final one ohm load. However, could they be ran in series and if so what ohm load would that result in?
Sean P Silver Member Username: Jbpitt Pittsburgh, Pa. Usa Post Number: 769 Registered: Jul-09	Posted on Sunday, September 05, 2010 - 20:29 GMT If ran in series i believe it would be 12 ohms
M.S. Platinum Member Username: Nd4spd18 Philadelphia, PA Post Number: 11346 Registered: Jul-06	Posted on Sunday, September 05, 2010 - 20:57 GMT parallel = impedance of one speaker / number of speakers 4 / 3 = 1.33 ohms series = impedance of one speaker * number of speakers 4 * 3 = 12 ohms
[...Rovin...] Platinum Member Username: Rovin 1 15 = 153 DBs ...Trinidad & T... Post Number: 16641 Registered: Jul-05	Posted on Monday, September 06, 2010 - 02:54 GMT newb alert ! - lol ... j\k rather than work it out i prefer to use the lazy guy method : http://www.rockfordfosgate.com/rftech/woofer_wizard.asp .....
SKD Gold Member Username: Skdooley Roanoke, VA Usa Post Number: 1181 Registered: Oct-09	Posted on Monday, September 06, 2010 - 03:23 GMT Good deal. I had no idea about the calculations like that.12 ohm would be insane Haha. Thanks for the info guys.